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- 66. 8 men can dig a pit in 20 days. If a man works half as much again a s a boy, then 4 men and 9 boys can dig a similar pit in:
A.10 days
B.12 days
C.15 days
D.16 days
Answer & Explanation
Answer: Option D 
1 work done = 8 × 20
1 man = 3/2 Boys
1 boy = 2/3 men
Then, 9 boys = 9 × 2/3 men = 6 men
Then, 4 men + 9 boys = 10 men
Then, 8 × 20 = 10 × ?days
? days = 8 × 20/10 = 16 days.
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- 67. A man and a boy complete a work together in 24 days. If for the last 6 days man alone does the work then it is completed in 26 days. How long the boy will take to complete the work alone?
A.72 days
B.20 days
C.24 days
D.36 days
Answer & Explanation
Answer: Option A
(man + boy)’s 1 day’s work = 1/24
Their 20 day’s work = 1/24 × 20 = 5/6
The remaining 1/6 work is done by the man in 6days
Therefore, the man alone will finish the work in 6 × 6 days = 36 days
Man’s 1 day’s work = 1/36
Therefore, boy’s 1 day’s work = 1/24 – 1/36 = 3 – 2 /72 = 1/72
Therefore, the Boy alone will finish the work in 72 days.
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- 68. A, B and C completed a piece of work costing Rs.1800. A worked for 6 days, B for 4 days and C for 9 days. If their daily wages are in the ratio 5 : 6 : 4, how much amount will be received by A?
A.Rs.800
B.Rs. 600
C.Rs.900
D.Rs.750
Answer & Explanation
Answer: Option B
The new ratio = wages ratio × No. of days
A = 5 × 6 = 30
B = 6 × 4 = 24
C = 4 × 9 = 36
Therefore, the ratio of the amount received = 30 : 24 : 36 = 5 : 4 :6
Total ratio = 15
1 unit of ratio = 1800/15 = Rs. 120
Therefore, amount received by A = 5 units = 5 × 120 = Rs.600.
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- 69. 12 men take 36 days to do a work while 12 women complete 3/4th of the same work in 36 days. In how many days 10 men and 8 women together will complete the same work?
A.6 days
B.12 days
C.27 days
D.None of these
Answer & Explanation
Answer: Option C
1 man’s 1 day’s work = 1/ 36 × 12 = 1/432
10 men’s 1 day’s work = 10/432
12 women can finish the whole work in 4 × 36/3 = 48 days
1 woman’s 1 days work = 1/ 48 × 12 = 1/576
8 women’s 1 day’s work = 8/572 = 1/72
(10 men + 8 women)’s 1 day’s work = 10/432 + 1/72 = 10 + 6/432 = 16/432
= 1/27
Therefore, the required No. of days = 27 days.
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- 70. A is thrice as good a workman as B and therefore is able to finish a job in 60 days less than B. working together, they can do it in
A.20 days
B.22 ½ days
C.25 days
D.30 days
Answer & Explanation
Answer: Option B
B = 3A
3A – A =60 days
A = 30days
Then, B = 90 days
(A + B) = 30 × 90/ 120 = 45/2 = 22 ½ days .
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