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- 36. A and B together can complete work in 4 days. A alone starts working and leaves it after working for 3 days completing only half of the work. In how many days it can be completed if the remaining job is undertaken by B?
A.4
B.8
C.5
D.6
Answer & Explanation
Answer: Option D 
(A+B) one day work =1/4
now A does half of the work in 3 days so A can complete the whole work in 6 days
A’s one day work =1/6
B’s one day work=1/4 - 1/6= 1/12
B alone can complete the work in 12 days so half of the work in 6 days
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- 37. In 12 pumps can raise 1218 tons of water in 11 days of 9 hrs each, how many pumps will raise 2030 tons of water in 12 days of 11 hrs each?
A.12
B.15
C.18
D.21
Answer & Explanation
Answer: Option B
pumps work time
12 1218 99
x 2030 132
=> 1218/(912*99) = 2020/(x × 132)
=> x = 15 pumps
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- 38. A can do a piece of work in 5 days and B can do it in 6 days how long will they both work together to complete the work?
A.2 6/11
B.2 8/11
C.2 7/11
D.2 9/11
Answer & Explanation
Answer: Option B
A’s one day work = 1/5
B’s one day work = 1/6
(A+B)’s one day work = 1/5 + 1/6 = 11/30 => time = 30/11 = 2 8/11 days
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- 39. If 3 men or 4 women can reap a field in 43 days how long will 7 men and 5 women take to reap it?
A.9
B.12
C.15
D.18
Answer & Explanation
Answer: Option B
3 men reap 1/43 field in 1 day
1 man reap 1/(3 x 43)
4 women reap 1/43 field in 1 day
1 woman reap 1/(43 x 4)
7 men and 5 women reap (7/(3 x 43)+ 5/(4 x 43)) =1/12 in 1 day
7 men and 5 women will reap the field in 12 days
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- 40. 4 pipes can fill a reservoir in 15, 20, 30 and 60 hrs the first was opened at 6 am and 2nd at 7 am and thirds at 8 am and 4th at 9 am when will the reservoir be full?
A.6 hrs
B.7 hrs
C.8 hrs
D.9 hrs
Answer & Explanation
Answer: Option B
let time be t hrs after 6 am
t/15 + (t-1)/30 + (t-2)/30 + (t-3)/60 =1
t = 7 hrs
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