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- 16. In Madan's opinion, his weight is greater than 65 kg but less than 72 kg. His brother does not agree with Madan and he thinks that Madan's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Madan?
A.68 kg
B.69 kg
C.67 kg
D.70 kg
Answer & Explanation
Answer: Option C 
Let Madan's weight = x. Then
According to Madan, 65 According to brother, 60 According to mother, x ≤ 68 ----(equation 3)
Given that equation 1,equation 2 and equation 3 are correct. By combining these equations,we can write as
65
Average of different probable weights of Madan = (66+67+68)/3 = 67
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- 17. A student's mark was wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by 1/2. What is the number of students in the class?
A.45
B.40
C.35
D.38
Answer & Explanation
Answer: Option B
Let the total number of students = x
The average marks increased by 1/2 due to an increase of 83 - 63 = 20 marks.
But total increase in the marks = 1/2 × x = x/2
Hence we can write as
x/2 = 20
⇒ x = 20 × 2 = 40
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- 18. The average salary of all the workers in a workshop is Rs.8000. The average salary of 7 technicians is Rs.12000 and the average salary of the rest is Rs.6000. How many workers are there in the workshop?
A.21
B.23
C.27
D.31
Answer & Explanation
Answer: Option A
Let the number of workers = x
Given that average salary of all the workers = Rs.8000
Then, total salary of all workers = 8000x
Given that average salary of 7 technicians is Rs.12000
=> Total salary of 7 technicians = 7 × 12000 = 84000
Count of the rest of the employees = (x - 7)
Average salary of the rest of the employees = Rs.6000
Total salary of the rest of the employees = (x - 7)(6000)
8000x = 84000 + (x - 7)(6000)
=> 8x = 84 + (x - 7)(6)
=> 8x = 84 + 6x - 42
=> 2x = 42
=> x = 42/2 = 21
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- 19. In an examination, a student's average marks were 63. If he had obtained 20 more marks for his Geography and 2 more marks for his history, his average would have been 65. How many subjects were there in the examination?
A.12
B.13
C.11
D.15
Answer & Explanation
Answer: Option C
Let the number of subjects = x
Then, total marks he scored for all subjects = 63x
If he had obtained 20 more marks for his Geography and 2 more marks for his history, his average would have been 65
=> Total marks he would have scored for all subjects = 65x
Now we can form the equation as 65x - 63x = additional marks of the student = 20 + 2 = 22
=> 2x = 22
=> x = 22/2 = 11
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- 20. The average age of a husband and his wife was 23 years at the time of their marriage. After five years they have a one year old child. What is the average age of the family ?
A.19 years
B.26 years
C.27 years
D.29 years
Answer & Explanation
Answer: Option A
Total age of husband and wife (at the time of their marriage) = 2 × 23 = 46
Total age of husband and wife after 5 years + Age of the 1 year old child
= 46 + 5 + 5 + 1 = 57
Average age of the family = 57/3 = 19
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