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- 1. The sides of a rectangle are in the ratio 4:3 and its area is 972sq.m find the perimeter of rectangle
A.120m
B.122m
C.124m
D.126m
Answer & Explanation
Answer: Option D 
let 4x and 3x be sides of the rectangle
We know that area of rectangle = l×b
4x × 3x = 972
12x2 = 972
X2 = 81
X = 9
Therefore length = 4x = 4×9 = 36m
Breadth = 3x = 3×9 = 27m
Therefore perimeter = 2 (l+b) = 2(36+27) = 126m
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- 2. Find the cost of carpenting a room 13m long and 9m broad with a carpet 75cm broad at the rate of Rs.20 per metre
A.Rs.3100
B.Rs.3120
C.Rs.3080
D.Rs.3112
Answer & Explanation
Answer: Option B
Area of the carpet = area of the room
= 13×9=117sq.m
Breadth of the carpet = 75cm = 3/4m
Length of the carpet = area/breadth (A=L×B=>L=A/B)
=117×4/3=156m
Hence, cost of carpet = 156×20 =Rs.3120
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- 3. The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq. cm. Find the length of the rectangle.
A.10 cm
B.15 cm
C.20 cm
D.18 cm
Answer & Explanation
Answer: Option C
Let breadth = x. Then, length = 2x. Then,
(2x - 5) (x + 5) - 2x * x = 75 => 5x - 25 = 75 => x = 20.
Length of the rectangle = 20 cm.
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- 4. If each side of a square is increased by 25%, find the percentage change in its area.
A.62.25
B.59.52
C.58.75
D.56.25
Answer & Explanation
Answer: Option D
Let each side of the square be a. Then, area = a2.
New side =(125a/100) =(5a/4). New area = (5a/4)2 =(25a2)/16.
Increase in area = ((25 a2)/16)-a2 =(9a2)/16.
Increase% = [((9a2)/16)×(1/a2)×100] % = 56.25%.
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- 5. A man walking at the rate of 6km per hour crosses a square field diagonally in 9 seconds the area of the field is
A.110sq.m
B.111.5aq.m
C.112.5sq.m
D.114sq.m
Answer & Explanation
Answer: Option C
Distance covered in 9 seconds = (6×1000/3600)×9 = 15m
Diagonal of square field = 15m
Side of square =a then diagonal of that square= √2 a
Hence area of the square = a2= (152)/2 =112.5 sq.m
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