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- 21. The inner circumference of a circular race track, 25 m wide, is 880 m. Find radius of the outer circle.
A.152m
B.156m
C.163m
D.165m
Answer & Explanation
Answer: Option D
Let inner radius be r metres. Then, 2Πr = 880 ⇔ r = (880 x (7/44))= 140 m.
Radius of outer circle = (140 + 25) m = 165 m.
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- 22. If the radius of a circle is decreased by 50%, find the percentage decrease in its area
A.52.5
B.60
C.72.5
D.75
Answer & Explanation
Answer: Option D
Let original radius = R. New radius =(50/100) R = (R/2)
Original area=Π( R )2= and new area= Π((R/2)2= (Π( R )2)/4
Decrease in area =((3Π(R )2 )/4 X (1/Π( R)2) X 100) % = 75%
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- 23. In two triangle, the ratio of the areas is 4:3 and that of their heights is 3:4 the ratio of their bases is
A.16:9
B.9:16
C.9:12
D.16:12
Answer & Explanation
Answer: Option A
Given a1/a2 =4/3, h1/h2=3/4
also, we know that
a1/a2=(1/2×b1×h1)/(1/2×b2×h2)
on substituting in above equation, we get
b1/b2= 16/9
therefore b1:b2= 16:9
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