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- 31. If A = x% of y and B = y% of x, then which of the following is true?
A.A is smaller than B.
B.Relationship between A and B cannot be determined.
C.A is greater than B.
D.None of these
Answer & Explanation
Answer: Option D 
A = (x/100)y = xy/100 .................(Equation 1)
B = (y/100)x = yx/100.................(Equation 2)
From these equations, it is clear that A = B
View Answer
- 32. 30% of the men are more than 25 years old and 80% of the men are less than or equal to 50 years old. 20% of all men play football. If 20% of the men above the age of 50 play football, what percentage of the football players are less than or equal to 50 years?
A.60%
B.80%
C.50%
D.90%
Answer & Explanation
Answer: Option B
Let total number of men = 100
Then
80 men are less than or equal to 50 years old
(Since 80% of the men are less than or equal to 50 years old)
=> 20 men are above 50 years old (Since we assumed total number of men as 100)20% of the men above the age of 50 play football⇒Number of men above the age of 50 who play football = 20 × 20/100 = 4
Number of men who play football = 20 (Since 20% of all men play football)
Percentage of men who play football above the age of 50 = 420 × 100 = 20%
=>Percentage of men who play football less than or equal to the age 50 = 100% − 20% = 80%
View Answer
- 33. Arun got 30% of the maximum marks in an examination and failed by 10 marks. However, Sujith who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?
A.90
B.250
C.85
D.75
Answer & Explanation
Answer: Option C
Let x is the maximum marks of the examination
Marks that Arun got = 30 % of x = 30x/100
Given that Arun failed by 10 marks
⇒Minimum Pass Mark = 30x/100 + 10......(Equation 1)
Marks that Sujith got = 40 % of x = 40x/100
Given that Sujith got 15 marks more than the passing marks
⇒40x100=Minimum Pass Mark +15
⇒Minimum Pass Mark =40 x100 −15......(Equation 2)
From equations 1 and 2, we have
30 x 100 + 10 = 40x/100 − 15
⇒10x/100 = 10 + 15 = 25
⇒x/10 = 25
⇒ x = 10 × 25 = 250
⇒Maximum marks of the examination = x = 250
Substituting the value of x in Equation 1, we have
Minimum Pass Mark = 30x/100 + 10 = 30 × 250/100 + 10 = 75 + 10 = 85
View Answer
- 34. On my sister's 15th birthday, she was 159 cm in height, having grown 6% since the year before. How tall was she the previous year?
A.150 cm
B.160 cm
C.170 cm
D.140 cm
Answer & Explanation
Answer: Option A
Given that height on 15th birthday = 159 cm and growth = 6%
Let the previous year height = x
Then height on 15th birthday = x × (100 + 6)/100 = x × 106/100
⇒159 = x × 106/100
⇒x = 159 × 100/106 = 1.5 × 100 = 150 cm
View Answer
- 35. If the price of petrol increases by 25% and Benson intends to spend only an additional 15% on petrol, by how much % will he reduce the quantity of petrol purchased?
A.8%
B.7%
C.10%
D.6%
Answer & Explanation
Answer: Option A
Assume that the initial price of 1 Litre petrol = Rs.100 ,Benson spends Rs.100 for petrol,
such that Benson buys 1 litre of petrol
After the increase by 25%, price of 1 Litre petrol = 100 × (100+25)/100 = Rs.125
Since Benson spends additional 15% on petrol,
amount spent by Benson = 100× (100+15)/100 = Rs.115
Hence Quantity of petrol that he can purchase = 115/125 Litre
Quantity of petrol reduced = (1−115/125) Litre
Percentage Quantity of reduction = (1−115125)/1 × 100 = 10/125 × 100 = 105 × 4 = 2 × 4 = 8%
View Answer
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