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- 16. The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 Km/hr. At what time will they meet?
A.10.30 a.m
B.11 a.m
C.10 a.m
D.12 noon
Answer & Explanation
Answer: Option B 
Assume that they meet x hours after 8 a.m.
Then,train1,starting from A , travelling towards B, travels x hours till the trains meet
⇒Distance travelled by train1 in x hours = Speed ×Time = 60x
Then, train2, starting from B , travelling towards A, travels (x-1) hours till the trains meet ⇒Distance travelled by train2 in (x-1) hours = Speed ×Time = 75(x-1) Total distance travelled = Distance travelled by train1 + Distance travelled by train2 => 330 = 60x + 75(x-1) => 12x + 15(x-1) = 66 => 12x + 15x - 15 = 66 => 27x = 66 + 15 = 81 => 3x = 9 => x = 3 Hence the trains meet 3 hours after 8 a.m., i.e. at 11 a.m.
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- 17. An athlete runs 200 metres race in 24 seconds. What is his speed?
A.20 km/hr
B.30 km/hr
C.25 km/hr
D.27.5 km/hr
Answer & Explanation
Answer: Option B
Speed = Distance/Time = 200/24 m/s=200/24 × 18/5 km/hr
= 40×34 km/hr = 10×3 km/hr = 30 km/hr
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- 18. Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5seconds after he sees it strike the tree. How far is the man from the wood chopper?
A.2420 ft
B.2810 ft
C.1800 ft
D.1820 ft
Answer & Explanation
Answer: Option A
Speed of the sound = 1100 ft/s
Time = 11/5 second
Distance = Speed × Time = 1100 ×11/5 = 220 × 11= 2420 ft
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- 19. The speed of a bus increases by 2 km after every one hour. If the distance travelling in the first one hour was 35 km. what was the total distance travelled in 12 hours?
A.552 km
B.502 km
C.492 km
D.422 km
Answer & Explanation
Answer: Option A
Given that distance travelled in 1st hour = 35 km
and speed of the bus increases by 2 km after every one hour
Hence distance travelled in 2nd hour = 37 km
Hence distance travelled in 3rd hour = 39 km
..
Total Distance Travelled = [35 + 37 + 39 + ... (12 terms)]
This is an Arithmetic Progression(AP) with
first term, a=35, number of terms,n = 12 and common difference, d=2.
The sequence a , (a + d), (a + 2d), (a + 3d), (a + 4d), . . .
is called an Arithmetic Progression(AP)
where a is the first term and d is the common difference of the AP
Sum of the first n terms of an Arithmetic Progression(AP),
Sn = n/2[2a+(n−1)d]
where n = number of terms
Hence, [35+37+39+... (12 terms)]
= S12 = 122[2 × 35 +(12 − 1)2]
= 6[70 + 22] = 6 × 92 = 552
Hence the total distance travelled = 552 km
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- 20. A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
A.7.2
B.4.2
C.6.1
D.7.2
Answer & Explanation
Answer: Option A
distance = 600 meter
time = 5 minutes = 5 x 60 seconds = 300 seconds
Speed = distance/time = 600/300 = 2m/s
= 2×185 km/hr = 365 km/hr = 7.2 km/hr
View Answer
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