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- 1. A person took some amount with some interest for 2 years, but increase the interest for 1%, he paid Rs.120/- extra, then how much amount he took?
A.Rs.5500/-
B.Rs.6000/-
C.Rs.4000/-
D.Rs.7000/-
Answer & Explanation
Answer: Option B
Explanation:2 years = Rs.120/-
year = 120/2
Rate of Interest = 1%
100/1% × 120/2 = Rs.6000/-
P = Rs.6000/-
View Answer
- 2. The rate of Interest on a sum of money is 2% p.a. for the first 3 years, 4% p.a. for the next 4 years, and 5% for the period beyond 7 years. If the S.I, Occured on the sum for the total period of 8 years is Rs. 540/-, the sum is
A.2,200
B.2,000
C.2,100
D.2,250
Answer & Explanation
Answer: Option B
Explanation:I1 = (P x 3 x 2)/100 = 3P/50
I2 = (P x 4 x 4)/100 = 4P/25
I3 = (P x 1 x 5)/100 = P/20
3P/50 + 4P/25 + P/20 = 540
The L.C.M of 50, 25, 20 = 100
(6P + 16P + 5P)/100 = 540
27P/100 = 540
27P = 54000
P = 54000/27
P = 2000
View Answer
- 3. A sum of 1200 lent at S.I at 10% will become twice in how many years?
A.12 years
B.14 years
C.10 years
D.8 years
Answer & Explanation
Answer: Option C
Explanation:To become twice means S.I should be as much as initial sum i.e, 1200
(1200 x 10 x T)/100 = 1200
T = 10 years
View Answer
- 4. At what rate p.a a sum of Rs. 2400 will become Rs. 3600/- in 5 years.
A.10%
B.15%
C.20%
D.12%
Answer & Explanation
Answer: Option A
Explanation:principal P = 2400/-
Rate of interest R = ?
Time T = 5 years
Accumulated Amount A = Rs.10400/-
A = P + I
A = P + PTR/100
A = P(1+ TR/100)
2400[ 1 + (5 x R)/100] = 3600
2[(20 + R)/20] = 3
20 + R = 30
R = 10%
View Answer
- 5. A sum when lent at S.I 3% per annum amount to Rs.840/- after 4 years
A.
B.
C.
D.
Answer & Explanation
Answer: Option
Explanation:P = ?
T = 4 years
R = 3%
S.I + P = 840
P(1 + (TR/100) = S.I + P
P[1 + (4 x 3)/100] = 840
P[(25 + 3)/25] = 840
P = 840 x (25/28)
P = 750
View Answer
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