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- 1. A train 100 m long is running at the speed of 30 km / hr. Find the time taken by it to pass a man standing near the railway line in seconds
A.5 sec
B.6 sec
C.7 sec
D.8 sec
Answer & Explanation
Answer: Option B 
Speed of the train = (60 x 5/18m / sec = 50/3 m/ sec.
Distance moved in passing the standing man = 100 m.
Required time taken = 100/(50/3) = (100 ×(3/50)) sec =6 sec
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- 2. A train 200 m long is running with a speed of 54 kmph. In what will it pass a car whose speed at 36 kmph in the direction opposite to that in which the train is going
A.8 sec
B.10 sec
C.12 sec
D.14 sec
Answer & Explanation
Answer: Option A
Speed of the train relative to man = (54 + 36) kmph
= 90 ×5/18 m/sec = 25 m/sec.
Time taken by the train to cross the car = Time taken by it to cover 200 m
at 25 m / sec = (200 ×1/25) sec = 8 sec
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- 3. Two trains 120 meters and 150 meters long are running in the same direction with speeds of 92 km/hr, 56km/hr. In how much time will the first train cross the second
A.37 sec
B.22 sec
C.27 sec
D.35sec
Answer & Explanation
Answer: Option C
Relative speed of the trains = (92 - 56) km/hr = 36 km/hr
= (36× 5/18) m/sec = 10 m/sec.
Time taken by the trains to cross each other
= Time taken to cover (120 + 150) m at 10 m /sec = (270/10) sec = 27 sec.
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- 4. A train is moving at a speed of 132 km/hr. If the length of the train is 100 meters, how long will it take to cross a railway platform 175 meters long
A.6 ½ sec
B.7 ½ sec
C.8 sec
D.8 ½ sec
Answer & Explanation
Answer: Option B
Speed of train = 132 ×(5/18) m/sec = 110/3 m/sec.
Distance covered in passing the platform = (100 + 175) m = 275 m.
Time taken =275 ×(3/110) sec =15/2 sec = 7 ½ sec
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- 5. A man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed
A.50 km
B.52 km
C.54 km
D.56 km
Answer & Explanation
Answer: Option C
Let the length of the train be x meters,
Then, the train covers x meters in 8 seconds and (x + 180) meters in 20 sec
x/8=(x+180)/20 ⇔ 20x = 8 (x + 180) x = 120
Length of the train = 120 m.
Speed of the train = (120/8)m / sec = m / sec = (15 ×18/5)kmph = 54 km
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To whom this Problems on Trains Questions and Answers section is beneficial?
Students can learn and improve on their skillset for using Verbal Ability effectively and can also prepare for competitive examinations like...
- All I.B.P.S and Public Sector Bank Competitive Exam
- Common Aptitude Test (CAT) Exams
- UPSC Paper-II or CSAT Exams
- SSC Competitive Exams
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- Railway Competitive Exam
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- Career Aptitude Test (IT Companies) and etc.
